Redox Reactions, Chemical Cells and Electrolysis
Subject: Chemistry
Megan (2026)
Date issued: 22 September 2026
Redox Reactions, Chemical Cells and Electrolysis
Multiple-Choice Questions
Choose the best answer for each question.
-
Sulfur dioxide reacts with hydrogen sulfide:
SO2 + 2H2S → 3S + 2H2OWhich statement is correct?
- Sulfur dioxide is oxidised.
- Hydrogen sulfide is reduced.
- Sulfur dioxide is the oxidising agent.
- The oxidation number of sulfur in both reactants increases.
-
Acidified permanganate ions oxidise iron(II) ions to iron(III) ions:
MnO4− + H+ + Fe2+ → Mn2+ + H2O + Fe3+What is the mole ratio of MnO4− to Fe2+ in the balanced equation?
- 1 : 2
- 1 : 5
- 2 : 5
- 5 : 1
-
Chlorine reacts with cold dilute sodium hydroxide:
Cl2 + 2OH− → Cl− + ClO− + H2OWhich statement is correct?
- Chlorine is oxidised only.
- Chlorine is reduced only.
- Chlorine is both oxidised and reduced.
- Hydroxide ions act as the oxidising agent.
-
The following electrochemical series is arranged in the DSE direction:
Which reaction occurs spontaneously?Oxidised form Electron change Reduced form K+ + e− ⇌ K Zn2+ + 2e− ⇌ Zn Fe2+ + 2e− ⇌ Fe 2H+ + 2e− ⇌ H2 Cu2+ + 2e− ⇌ Cu Cl2 + 2e− ⇌ 2Cl− F2 + 2e− ⇌ 2F− - Cu + Zn2+ → Cu2+ + Zn
- Fe + Cu2+ → Fe2+ + Cu
- 2Cl− + 2F− → Cl2 + F2
- Cu + 2H+ → Cu2+ + H2
-
A zinc–copper chemical cell consists of zinc–zinc ion and
copper–copper ion half-cells connected by a salt bridge.
Which statement is correct when the cell operates?
- The zinc electrode is the positive electrode.
- Electrons flow from copper to zinc.
- The concentration of zinc ions decreases.
- Anions in the salt bridge migrate towards the zinc half-cell.
-
A chemical cell contains these two half-cells:
- Fe3+(aq)/Fe2+(aq), with a platinum electrode
- I2(aq)/I−(aq), with a platinum electrode
2Fe3+ + 2I− → 2Fe2+ + I2Which statement is correct?- Iron(III) ions are oxidised.
- Iodide ions are reduced.
- Electrons flow from the iodine half-cell to the iron half-cell.
- The platinum electrode in the iodine half-cell gains mass.
-
Concentrated sodium chloride solution is electrolysed using graphite electrodes.
Which combination is correct?
Option Cathode product Anode product Main product remaining in solution A Sodium Chlorine Hydrochloric acid B Hydrogen Chlorine Sodium hydroxide C Hydrogen Oxygen Sodium hydroxide D Sodium Oxygen Sodium hydroxide - Combination A
- Combination B
- Combination C
- Combination D
-
Dilute and concentrated sodium chloride solutions are separately
electrolysed using inert electrodes.
Which statement is correct?
- Sodium is formed at the cathode of the concentrated solution.
- Chlorine is always formed at the anode, regardless of concentration.
- Hydrogen is normally formed at the cathode in both experiments.
- Oxygen is formed at the cathode of the dilute solution.
-
Aqueous copper(II) sulfate is electrolysed in two experiments:
- Experiment I uses graphite electrodes.
- Experiment II uses copper electrodes.
- Copper is deposited at the cathode only in Experiment II.
- Oxygen is formed at the anode in both experiments.
- The blue colour becomes paler more readily in Experiment I.
- The copper anode gains mass in Experiment II.
-
A steel spoon is to be electroplated with copper.
Which arrangement is correct?
Option Cathode Anode Electrolyte A Steel spoon Copper Copper(II) sulfate solution B Copper Steel spoon Copper(II) sulfate solution C Steel spoon Graphite Sodium sulfate solution D Copper Graphite Copper(II) sulfate solution - Arrangement A
- Arrangement B
- Arrangement C
- Arrangement D
Redox Reactions and Electrochemistry
True or False
Write “True” or “False” for each statement. If a statement is false, rewrite it correctly.
- Oxidation must involve the gain of oxygen.
- A reducing agent causes another substance to be reduced and is itself oxidised.
- In a polyatomic ion, the sum of the oxidation numbers of all the atoms is equal to the charge of the ion.
- In a chemical cell that generates electricity, oxidation occurs at the negative electrode.
- Electrons move through the salt bridge from one half-cell to the other.
- A salt bridge completes the circuit and helps maintain electrical neutrality in the two half-cells.
- An inert electrode conducts electrons but does not normally take part in the overall chemical reaction.
- Oxidation always occurs at the anode, although the sign of the anode is different in a chemical cell and an electrolytic cell.
- During the electrolysis of concentrated sodium chloride solution, sodium ions are preferentially discharged because their concentration is high.
- During the electrolysis of copper(II) sulfate solution using copper electrodes, the copper(II) ion concentration remains approximately constant.
Electrolysis
Electrolysis of Copper(II) Sulfate Solution
A student electrolyses aqueous copper(II) sulfate using graphite electrodes. The solution is initially blue.
- Name the ions present in the solution before electrolysis. [2]
-
State which ions or molecules are preferentially discharged at:
- the cathode;
- the anode.
-
Write an ionic half-equation for the reaction at:
- the cathode;
- the anode.
- State two observations at the cathode. [2]
- State one observation at the anode and describe a chemical test for the product formed. [3]
-
State and explain the change in:
- the intensity of the blue colour;
- the acidity of the solution.
- Write the overall equation for the electrolysis. [2]
-
The experiment is repeated using copper electrodes.
State and explain:
- the change in mass of the cathode;
- the change in mass of the anode;
- the change in copper(II) ion concentration;
- whether a gas is formed at the anode.
-
A student claims:
“Graphite and copper are both electrical conductors, so using them as anodes must give the same product.”Explain why this statement is incorrect. [2]
Preferential Discharge and Electroplating
Sodium Chloride Solutions and Copper Plating
The relevant electrochemical series is shown below in the DSE direction.
| Oxidised form | Electron change | Reduced form |
|---|---|---|
| K+ | + e− ⇌ | K |
| Na+ | + e− ⇌ | Na |
| 2H2O | + 2e− ⇌ | H2 + 2OH− |
| O2 + 4H+ | + 4e− ⇌ | 2H2O |
| Cl2 | + 2e− ⇌ | 2Cl− |
| F2 | + 2e− ⇌ | 2F− |
Two sodium chloride solutions are electrolysed using graphite electrodes:
- Cell A contains dilute sodium chloride solution.
- Cell B contains concentrated sodium chloride solution.
-
For both cells:
- state the product formed at the cathode;
- write the cathodic half-equation;
- explain why sodium is not formed.
-
For Cell A:
- state the expected product at the anode;
- write the anodic half-equation;
- describe a test for the product.
-
For Cell B:
- state the expected product at the anode;
- write the anodic half-equation;
- describe two observations at the anode;
- describe a chemical test for the product.
- Explain why different products may be formed at the anodes of Cells A and B even though both electrolytes contain the same types of ions. [2]
- State the main substance that accumulates in Cell B after electrolysis. Explain your answer using the ions remaining or formed in the solution. [3]
- Explain why the gaseous products should be collected separately rather than allowed to mix. [2]
A student then wants to electroplate an iron key with copper using copper(II) sulfate solution.
-
State what should be used as:
- the cathode;
- the anode;
- the electrolyte.
- Before electroplating, the iron key is cleaned carefully. Explain why this is necessary. [2]
- Write the half-equations at the two electrodes during electroplating. [2]
-
State and explain the expected change in:
- the mass of the iron key;
- the mass of the copper electrode;
- the intensity of the blue colour of the electrolyte.
- State one possible environmental problem caused by the improper disposal of waste from an electroplating factory. [1]
Question 1 — Multiple-Choice Questions
-
C — Sulfur dioxide is the oxidising agent.
Sulfur in SO2 decreases from +4 to 0, so SO2 is reduced. Sulfur in H2S increases from −2 to 0, so H2S is oxidised.
-
B — 1 : 5.
MnO4− + 8H+ + 5Fe2+ → Mn2+ + 4H2O + 5Fe3+
-
C — Chlorine is both oxidised and reduced.
Chlorine changes from oxidation number 0 to −1 in Cl− and from 0 to +1 in ClO−.
-
B — Fe + Cu2+ → Fe2+ + Cu.
Iron is oxidised to iron(II) ions, while copper(II) ions are reduced to copper.
-
D — Anions in the salt bridge migrate towards the zinc half-cell.
Zinc is oxidised to Zn2+. Anions migrate into the zinc half-cell to counteract the increasing positive charge.
-
C — Electrons flow from the iodine half-cell to the iron half-cell.
Iodide ions are oxidised in the iodine half-cell, while iron(III) ions are reduced in the iron half-cell.
-
B — Hydrogen, chlorine and sodium hydroxide.
Hydrogen is formed at the cathode, chlorine is formed at the anode, and sodium hydroxide accumulates in the solution.
-
C — Hydrogen is normally formed at the cathode in both experiments.
Water is reduced preferentially instead of sodium ions in aqueous sodium chloride.
-
C — The blue colour becomes paler more readily in Experiment I.
In Experiment I, Cu2+ ions are removed at the graphite cathode but are not replaced at the graphite anode.
- A — Steel spoon as the cathode, copper as the anode and copper(II) sulfate solution as the electrolyte.
Question 2 — True or False
- False. Oxidation can be defined as loss of electrons or an increase in oxidation number. It does not always involve oxygen.
- True. A reducing agent supplies electrons to another substance and is itself oxidised.
- True. The total of all oxidation numbers in a polyatomic ion equals the overall charge of the ion.
- True. In a chemical cell, oxidation occurs at the negative electrode, which is the anode.
- False. Electrons move through the external circuit. Ions move through the salt bridge.
- True. The salt bridge completes the circuit and helps maintain electrical neutrality in both half-cells.
- True. An inert electrode provides a conducting surface without normally taking part in the overall reaction.
- True. Oxidation always occurs at the anode. The anode is negative in a chemical cell but positive in an electrolytic cell.
- False. Water is preferentially reduced at the cathode, producing hydrogen. Sodium is not deposited from aqueous sodium chloride.
- True. Copper(II) ions removed at the cathode are approximately replaced by copper(II) ions formed at the copper anode.
Question 3 — Electrolysis of Copper(II) Sulfate Solution
-
The ions present are:
Cu2+, SO42−, H+ and OH−
H+ and OH− are present because the electrolyte is an aqueous solution.
-
Cathode: Cu2+ ions are
preferentially discharged and reduced.
Anode: Water or hydroxide ions are preferentially oxidised because sulfate ions are difficult to discharge. -
Cathode:
Cu2+ + 2e− → CuAnode:4OH− → O2 + 2H2O + 4e−
The equivalent water half-equation is also acceptable:
2H2O → O2 + 4H+ + 4e− -
- A reddish-brown solid is deposited.
- The graphite cathode gains mass.
- Bubbles of a colourless gas are produced at the anode. A glowing splint relights in the gas, showing that it is oxygen.
-
Blue colour: The blue colour becomes paler
because Cu2+ ions are removed from the solution
and deposited as copper.
Acidity: The solution becomes more acidic because the overall electrolysis produces H+ ions. -
The overall equation is:
2CuSO4 + 2H2O → 2Cu + O2 + 2H2SO4
-
At the cathode:
Cu2+ + 2e− → Cu
The cathode gains mass because copper is deposited on it.
At the copper anode:Cu → Cu2+ + 2e−The anode loses mass because copper atoms enter the solution as Cu2+ ions.
The Cu2+ concentration remains approximately constant because the ions removed at the cathode are replaced at the anode. No gas is normally formed at the copper anode.
- The nature of an electrode can affect the electrode reaction. Graphite is inert, so water or hydroxide ions are oxidised. Copper is an active electrode and is itself oxidised to copper(II) ions.
Question 4 — Preferential Discharge and Electroplating
-
Hydrogen is formed at the cathode in both cells.
2H2O + 2e− → H2 + 2OH−
Water is reduced more readily than sodium ions. Sodium is therefore not deposited from the aqueous electrolyte.
-
Oxygen is expected at the anode of Cell A.
4OH− → O2 + 2H2O + 4e−
A glowing splint relights in the gas.
-
Chlorine is formed at the anode of Cell B.
2Cl− → Cl2 + 2e−
Bubbles of a greenish-yellow gas are produced. The gas has a pungent or choking smell.
Chlorine turns damp blue litmus paper red and then bleaches it white.
- Ion concentration affects preferential discharge. At a high chloride ion concentration, chloride ions are preferentially discharged. At a low chloride ion concentration, water or hydroxide ions are preferentially discharged.
-
Sodium hydroxide accumulates in Cell B when the electrode
products are kept separate.
Hydrogen and hydroxide ions are formed at the cathode, while chloride ions are removed at the anode. Sodium ions and hydroxide ions therefore remain in the solution.
- Hydrogen and chlorine can react explosively, particularly in bright light. The gases should therefore be collected separately.
-
- Cathode: iron key
- Anode: copper
- Electrolyte: copper(II) sulfate solution
- Grease, dirt and oxide layers would prevent copper from adhering evenly and firmly to the surface of the key. Cleaning produces a smooth and durable copper coating.
-
Cathode:
Cu2+ + 2e− → CuAnode:Cu → Cu2+ + 2e−
-
Iron key: The key gains mass because copper
is deposited on it.
Copper electrode: The copper anode loses mass because copper atoms are oxidised to Cu2+ ions.
Blue colour: The blue colour remains approximately unchanged because Cu2+ ions removed at the cathode are replaced at the copper anode. - Waste containing metal ions may pollute water and harm aquatic organisms. It may also contaminate soil or enter food chains.
Redox, Chemical Cells and Electrolysis Reference
Reduction = gain of electrons
Reduction = decrease in oxidation number
Reduction occurs at the cathode.
