IGCSE Chemistry Recap: Topics 1–9
Subject: IGCSE Chemistry
Ho Him (2026)
Date issued: 22 September 2026
Topics 1–9
Multiple-Choice Questions
Choose the best answer for each question. Each question carries one mark.
-
A pure solid is heated at a constant rate. Its temperature rises from 20°C to 65°C, remains constant for four minutes, and then rises again. Which statement explains the period at 65°C?
- The particles stop moving while the solid melts.
- The energy supplied is used to overcome attractive forces between particles.
- The particles lose kinetic energy as the solid changes into a liquid.
- The energy supplied increases the average speed of the particles.
-
A fixed mass of gas is sealed in a flexible container. Its temperature is increased while the external pressure remains constant. Why does the volume increase?
- The gas particles become larger.
- The number of gas particles increases.
- The particles move faster and become farther apart while maintaining the same pressure.
- The attractive forces between the gas particles become much stronger.
-
Hydrogen chloride gas and ammonia gas are released simultaneously at opposite ends of a long tube. A white ring forms closer to the hydrogen chloride end. What is the best explanation?
- Hydrogen chloride particles are smaller than ammonia particles.
- Ammonia has a lower relative molecular mass and diffuses faster.
- Hydrogen chloride has a higher concentration and diffuses faster.
- Ammonia molecules are more strongly attracted to the walls of the tube.
-
A gas occupies 120 cm³ at a particular temperature and pressure. Its pressure is doubled at constant temperature. Which volume is expected?
- 60 cm³ because particles collide with the walls more frequently in a smaller volume.
- 60 cm³ because half of the gas particles escape.
- 240 cm³ because the particles move twice as fast.
- 240 cm³ because the spaces between the particles double.
-
Four particles are represented below.
Which statement is correct?Particle Protons Neutrons Electrons P 16 16 18 Q 16 18 16 R 18 22 18 S 17 18 18 - P and Q are isotopes of the same element.
- Q and R are atoms of the same element.
- P and S have the same charge.
- R and S are isotopes of the same element.
-
An element has three naturally occurring isotopes.
Its relative atomic mass is 24.40. What is the abundance of the isotope with mass 24?Relative isotopic mass Percentage abundance 24 Unknown 25 10% 26 15% - 65%
- 70%
- 75%
- 80%
-
Substance X has a high melting point. It does not conduct electricity when solid but conducts when molten. Which description is correct?
- It is a simple molecular substance containing weak covalent bonds.
- It is an ionic compound containing ions that become mobile when molten.
- It is a metal containing positive ions that become mobile when molten.
- It is a giant covalent substance containing delocalised electrons.
-
Element M has the electron arrangement 2,8,2. Element N has the electron arrangement 2,7. Which formula and bonding are expected?
- MN, covalent
- MN2, ionic
- M2N, ionic
- M2N7, covalent
-
Aluminium reacts with chlorine.
2Al + 3Cl2 → 2AlCl3A mixture contains 5.4 g of aluminium and 14.2 g of chlorine. What is the maximum mass of aluminium chloride formed?
Use: Ar(Al) = 27 and Ar(Cl) = 35.5.
- 8.9 g
- 13.4 g
- 17.8 g
- 26.7 g
-
Calcium carbonate reacts with excess hydrochloric acid.
CaCO3 + 2HCl → CaCl2 + H2O + CO2What volume of carbon dioxide at r.t.p. is produced from 5.0 g of pure calcium carbonate?
Use: Mr(CaCO3) = 100; molar gas volume = 24 dm³.
- 0.60 dm³
- 1.20 dm³
- 2.40 dm³
- 4.80 dm³
-
A compound contains 40.0% carbon, 6.7% hydrogen and 53.3% oxygen by mass. Its relative molecular mass is 180. What is its molecular formula?
- CH2O
- C2H4O2
- C3H6O3
- C6H12O6
-
25.0 cm³ of sodium hydroxide is neutralised by 20.0 cm³ of 0.150 mol/dm³ sulfuric acid.
H2SO4 + 2NaOH → Na2SO4 + 2H2OWhat is the concentration of sodium hydroxide?
- 0.120 mol/dm³
- 0.150 mol/dm³
- 0.240 mol/dm³
- 0.300 mol/dm³
-
Molten lead(II) bromide is electrolysed using inert electrodes. Which products form?
Option Cathode Anode A Bromine Lead B Lead Bromine C Hydrogen Oxygen D Lead Oxygen - Pair A
- Pair B
- Pair C
- Pair D
-
Aqueous copper(II) sulfate is electrolysed using inert graphite electrodes. Which changes occur?
- Copper forms at the cathode, oxygen at the anode, and the blue colour becomes paler.
- Hydrogen forms at the cathode, copper at the anode, and the blue colour becomes darker.
- Copper forms at both electrodes, and the concentration remains unchanged.
- Oxygen forms at both electrodes, and the solution becomes neutral.
-
Concentrated aqueous sodium chloride is electrolysed using inert electrodes. Which products form?
Option Cathode Anode Substance remaining in solution A Sodium Chlorine Hydrochloric acid B Hydrogen Chlorine Sodium hydroxide C Hydrogen Oxygen Sodium chloride only D Sodium Oxygen Sodium hydroxide - Pair A
- Pair B
- Pair C
- Pair D
-
Aqueous copper(II) sulfate is electrolysed using copper electrodes. Which statement is correct?
- The cathode loses mass and the anode gains mass.
- Both electrodes gain mass.
- The anode loses mass, the cathode gains mass, and the Cu2+ concentration remains approximately constant.
- Oxygen forms at the anode and the blue colour fades rapidly.
-
In a reaction pathway, the reactants are at 80 kJ/mol, the products at 20 kJ/mol and the maximum point at 140 kJ/mol. Which values are correct?
Option Forward activation energy Enthalpy change A 60 kJ/mol −60 kJ/mol B 60 kJ/mol +60 kJ/mol C 120 kJ/mol −60 kJ/mol D 140 kJ/mol +20 kJ/mol - Pair A
- Pair B
- Pair C
- Pair D
-
Hydrogen reacts with chlorine.
H2 + Cl2 → 2HClBond energies are: H–H = 436 kJ/mol, Cl–Cl = 243 kJ/mol and H–Cl = 431 kJ/mol. What is the enthalpy change?
- −183 kJ/mol
- −110 kJ/mol
- +183 kJ/mol
- +679 kJ/mol
-
A catalyst is added to an exothermic reaction. Which statement is correct?
- It makes the enthalpy change more negative.
- It lowers the activation energy of both forward and reverse reactions.
- It increases the energy level of the products.
- It increases the energy released per mole.
-
An instant cold pack becomes cold when a salt dissolves in water. Which statement is correct?
- The process is exothermic because bond breaking releases energy.
- The process is exothermic because energy transfers to the surroundings.
- The process is endothermic because it takes in thermal energy from the surroundings.
- The process is endothermic because the products have less energy than the reactants.
-
Calcium carbonate reacts with excess dilute hydrochloric acid. The experiment is repeated using the same mass of smaller calcium carbonate particles. Which change is expected?
- A lower initial rate and more carbon dioxide.
- A higher initial rate and the same final volume of carbon dioxide.
- A higher initial rate and more carbon dioxide.
- The same initial rate, but the reaction finishes sooner.
-
A catalyst increases reaction rate because it:
- increases reactant concentration.
- increases the energy released by successful collisions.
- provides an alternative pathway with a lower activation energy.
- increases the kinetic energy of every reactant particle.
-
The following equilibrium is established in a closed container.
N2O4(g) ⇌ 2NO2(g)The forward reaction is endothermic. Which changes favour NO2 formation?
- Decrease temperature and increase pressure.
- Decrease temperature and decrease pressure.
- Increase temperature and increase pressure.
- Increase temperature and decrease pressure.
-
Iron(III) oxide is reduced by carbon monoxide.
Fe2O3 + 3CO → 2Fe + 3CO2Which statement is correct?
- Iron(III) oxide is oxidised because it loses oxygen.
- Carbon monoxide is reduced because it gains oxygen.
- Iron(III) oxide is reduced and carbon monoxide is oxidised.
- Iron and carbon dioxide are both reducing agents.
-
A solution of pH 2 is diluted with a large volume of water. Which statement is correct?
- Its pH decreases because it contains more water.
- Its pH increases, but the solution normally remains acidic.
- Its pH immediately becomes 7 because water is neutral.
- Its hydrogen-ion concentration increases.
-
Which method is most suitable for preparing pure, dry copper(II) sulfate crystals?
- Add excess copper to dilute sulfuric acid and evaporate to dryness.
- Add excess copper(II) oxide to warm dilute sulfuric acid, filter, concentrate and crystallise.
- Mix copper(II) chloride solution with sodium sulfate solution and filter.
- Titrate copper(II) oxide with sulfuric acid using an indicator.
-
Which pair of aqueous solutions produces a precipitate when mixed?
- Sodium nitrate and potassium chloride
- Hydrochloric acid and sodium hydroxide
- Barium nitrate and sodium sulfate
- Ammonium chloride and sodium nitrate
-
An ammonium salt is warmed with aqueous sodium hydroxide. Which observation and conclusion are correct?
- A colourless gas turns damp red litmus paper blue; ammonia is produced.
- A colourless gas turns damp blue litmus paper red; carbon dioxide is produced.
- A green precipitate forms; ammonium ions are present.
- A white precipitate forms; hydroxide ions are present.
-
Element X has the electron arrangement 2,8,7. Which statement is correct?
- X is in Group VII and Period 3 and tends to gain one electron.
- X is in Group VII and Period 2 and tends to lose one electron.
- X is in Group III and Period 7 and tends to gain three electrons.
- X is in Group VIII and Period 3 and is unreactive.
-
Which trends are observed down Group I?
- Atomic radius decreases, melting point increases and reactivity decreases.
- Atomic radius increases, melting point generally decreases and reactivity increases.
- Atomic radius increases, melting point increases and reactivity decreases.
- Atomic radius decreases, melting point decreases and reactivity increases.
-
Chlorine water is added separately to aqueous potassium bromide and aqueous potassium iodide. Which statement is correct?
- Chlorine displaces bromine only because iodine is more reactive.
- Chlorine displaces iodine only because bromine is more reactive.
- Chlorine displaces both bromine and iodine because chlorine is more reactive.
- No reaction occurs because halogens cannot displace halide ions.
-
Which property is characteristic of transition elements but not Group I metals?
- They form only colourless compounds.
- They have low densities and low melting points.
- They form ions with only a +1 charge.
- They may form coloured compounds and act as catalysts.
-
Metal X is below carbon but above hydrogen in the reactivity series.
1. X can be extracted from its oxide using carbon.
2. X reacts with dilute hydrochloric acid.
3. X can be extracted from an aqueous solution of its salt by electrolysis only.
Which statements are correct?- 1 and 2 only
- 1 and 3 only
- 2 and 3 only
- 1, 2 and 3
-
Four iron nails are treated as shown.
Which order shows increasing rate of rusting?Nail Conditions P Dry air only Q Boiled water covered with oil R Air and water S Salt water exposed to air - P = Q < R < S
- P < Q < S < R
- R < S < P = Q
- Q < R < P < S
-
Why is an alloy usually harder than the pure metal from which it is made?
- The alloy contains no delocalised electrons.
- Different-sized atoms distort the layers and make sliding more difficult.
- The atoms in the alloy form simple molecules.
- The alloy contains weaker metallic bonds that break less easily.
-
Magnesium, zinc and copper are separately added to cold water, steam and dilute hydrochloric acid. Which statement is correct?
- Copper reacts with dilute hydrochloric acid to form hydrogen.
- Zinc reacts rapidly with cold water but not with steam.
- Magnesium reacts with steam and dilute hydrochloric acid.
- All three metals react with cold water to form hydroxides.
Topic 1: States of Matter
Heating and Particle Behaviour
A pure substance is heated at a constant rate. The results are shown.
| Time/min | 0 | 2 | 4 | 6 | 8 | 10 | 12 | 14 |
|---|---|---|---|---|---|---|---|---|
| Temperature/°C | 20 | 36 | 52 | 68 | 68 | 68 | 83 | 98 |
- State the melting point of the substance. [1]
-
Describe the arrangement and movement of the particles:
- before heating begins;
- during the constant-temperature section;
- after the substance has completely melted.
- Explain why the temperature remains constant from 6 to 10 minutes even though heating continues. [2]
- The liquid is heated until it becomes a gas. Explain why the gas occupies the whole container. [2]
- The gas is compressed at constant temperature. Explain, in terms of particles, why its pressure increases. [2]
- Gas X diffuses more slowly than gas Y under the same conditions. What can be concluded about their relative molecular masses? Explain your answer. [2]
Topic 2: Atoms, Elements and Compounds
Atomic Structure, Isotopes and Bonding
Element X has a proton number of 13. It has two naturally occurring isotopes, X-27 and X-29. Its relative atomic mass is 27.2.
-
Complete the table. [6]
Particle Protons Neutrons Electrons X-27 atom X-29 atom X3+ ion formed from X-27 - Define the term isotope. [2]
- Calculate the percentage abundance of X-29. [3]
-
Write the electron arrangement of:
- an atom of X;
- an X3+ ion.
-
Element Y has the electron arrangement 2,8,7.
- Explain how X and Y form ions.
- Deduce the formula of the compound formed.
- State the type of bonding present.
- Explain why the compound formed between X and Y has a high melting point and conducts electricity when molten but not when solid. [4]
Topic 3: Stoichiometry
Reacting Masses, Gas Volumes and Yield
Magnesium reacts with dilute hydrochloric acid.
A student adds 3.60 g of magnesium to hydrochloric acid containing 0.200 mol of HCl. Use Ar(Mg) = 24 and a molar gas volume of 24 dm³ at r.t.p.
- Calculate the amount, in moles, of magnesium used. [2]
- Determine the limiting reactant. Show your working. [3]
- Calculate the amount, in moles, of hydrogen formed. [1]
- Calculate the volume of hydrogen produced at r.t.p. [2]
- Calculate the mass of the reactant remaining when the reaction is complete. [3]
- The actual volume of hydrogen collected is 2.16 dm³. Calculate the percentage yield. [2]
- A 4.00 g sample of impure magnesium reacts with excess hydrochloric acid and produces 3.60 dm³ of hydrogen at r.t.p. Calculate the percentage purity of the magnesium sample. [4]
Topic 4: Electrochemistry
Electrolysis and Electroplating
Aqueous copper(II) sulfate is electrolysed in two experiments. Experiment 1 uses graphite electrodes. Experiment 2 uses copper electrodes.
- Define electrolysis. [2]
-
For Experiment 1:
- state the product at the cathode;
- state the product at the anode;
- describe the observation at each electrode;
- describe the change in the colour of the solution.
-
Write an ionic half-equation for the reaction at:
- the cathode;
- the anode.
-
For Experiment 2:
- describe the change in mass of each electrode;
- explain why the concentration of Cu2+ remains approximately constant.
-
A steel spoon is electroplated with silver. State:
- which electrode the spoon should form;
- a suitable material for the other electrode;
- a suitable electrolyte;
- one reason for electroplating.
- State one advantage and one disadvantage of using hydrogen–oxygen fuel cells rather than petrol engines in vehicles. [2]
Topic 5: Chemical Energetics
Bond Energies and Reaction Pathways
Methane burns completely in oxygen.
| Bond | Bond energy in kJ/mol |
|---|---|
| C–H | 413 |
| O=O | 498 |
| C=O in CO2 | 805 |
| O–H | 464 |
-
State what is meant by:
- an exothermic reaction;
- activation energy.
- Calculate the total energy needed to break all the bonds in the reactants. [3]
- Calculate the total energy released when all the bonds in the products form. [3]
- Calculate the enthalpy change. Include its sign and unit. [3]
- Explain the sign of the enthalpy change in terms of bond breaking and bond making. [2]
- Sketch a labelled reaction pathway diagram showing the reactants, products, activation energy and enthalpy change. [4]
- On the same diagram, show the pathway when a catalyst is used. Explain why the catalyst increases reaction rate but does not change the enthalpy change. [3]
Topic 6: Chemical Reactions
Rates, Equilibrium and Redox
A student investigates the reaction between calcium carbonate and dilute hydrochloric acid.
| Experiment | Calcium carbonate | Hydrochloric acid | Temperature |
|---|---|---|---|
| 1 | 5.0 g large chips | 50 cm³ of 1.0 mol/dm³ | 20°C |
| 2 | 5.0 g small chips | 50 cm³ of 1.0 mol/dm³ | 20°C |
| 3 | 5.0 g small chips | 50 cm³ of 2.0 mol/dm³ | 20°C |
| 4 | 5.0 g small chips | 50 cm³ of 2.0 mol/dm³ | 35°C |
- Which experiment has the greatest initial rate? Explain using collision theory. [4]
-
Compare Experiments 1 and 2.
- Which finishes first?
- Do they produce the same final volume of carbon dioxide?
- Explain both answers.
- Explain how increasing temperature increases reaction rate. Refer to particle speed, collision frequency, activation energy and successful collisions. [4]
-
The following equilibrium is established in a closed container:
N2O4(g) ⇌ 2NO2(g)The forward reaction is endothermic. Predict and explain the effect of:
- increasing temperature;
- increasing pressure.
-
For the reaction below, identify the substance oxidised, the substance reduced and the reducing agent.
Fe2O3 + 3CO → 2Fe + 3CO2[3]
Topic 7: Acids, Bases and Salts
Salt Preparation and Neutralisation
A student prepares hydrated copper(II) sulfate crystals using copper(II) oxide and dilute sulfuric acid.
- Write the word equation and balanced symbol equation for the reaction. [3]
- Explain why copper metal is not normally used to prepare copper(II) sulfate directly from dilute sulfuric acid. [1]
-
The student warms the acid, adds copper(II) oxide, filters the mixture, heats the filtrate, cools the solution, and filters and dries the crystals. Explain:
- why copper(II) oxide is added until some remains unreacted;
- why the mixture is filtered;
- why the filtrate is not heated to complete dryness;
- why the concentrated solution is cooled.
-
25.0 cm³ of sodium hydroxide is neutralised by 18.0 cm³ of 0.250 mol/dm³ sulfuric acid.
H2SO4 + 2NaOH → Na2SO4 + 2H2OCalculate the concentration of sodium hydroxide. [4]
- A student wants to prepare pure, dry barium sulfate. Name two suitable aqueous solutions and describe the procedure. [4]
-
Write:
- the ionic equation for neutralisation;
- the ionic equation for barium sulfate formation.
- Describe a test for ammonium ions and give the positive result. [2]
Topic 8: The Periodic Table
Periodic Trends and Group Properties
| Element | Information |
|---|---|
| P | Electron arrangement 2,8,1 |
| Q | Electron arrangement 2,8,7 |
| R | A monatomic gas with electron arrangement 2,8,8 |
| S | A metal that forms coloured compounds and ions with different charges |
| T | A Group I metal below P |
- Identify P, Q and R. [3]
- State the group and period of P and Q. [4]
- Explain why R is very unreactive. [2]
- Predict how the reaction of T with water differs from the reaction of P with water. Explain using occupied electron shells, shielding, nuclear attraction and loss of the outer electron. [5]
-
Chlorine, bromine and iodine are added separately to solutions containing halide ions.
- State the order of reactivity of the three halogens.
- State which halogen displaces bromide ions but not chloride ions.
- Write an ionic equation for chlorine reacting with iodide ions.
- Describe two characteristic properties of transition elements illustrated by S. [2]
- State the trend in the colour of the halogens down Group VII and explain why their melting and boiling points increase. [3]
Topic 9: Metals
Reactivity, Extraction and Corrosion
| Metal | Reaction with cold water | Reaction with dilute hydrochloric acid | Reaction of oxide with carbon |
|---|---|---|---|
| W | Very vigorous | Not tested | Oxide not reduced |
| X | No reaction | Rapid reaction | Oxide is reduced |
| Y | No reaction | No reaction | Oxide is reduced |
| Z | Slow reaction | Vigorous reaction | Oxide not reduced |
- Arrange W, X, Y and Z in decreasing order of reactivity. Explain your reasoning. [4]
-
Which metal could be:
- potassium;
- zinc;
- copper?
- Explain why highly reactive metals are extracted by electrolysis, whereas less reactive metals may be extracted by reducing their oxides with carbon. [3]
-
Iron is extracted from iron(III) oxide using carbon monoxide.
- Write the balanced equation.
- Identify the substance oxidised.
- Identify the substance reduced.
- Explain why aluminium is used in aircraft bodies, overhead electrical cables and food containers. [3]
- Explain, in terms of structure, why an alloy is generally harder than a pure metal. [3]
- State the two substances required for iron to rust. Explain why iron rusts faster in salt water than in pure water. [3]
- Describe two different methods of preventing iron from rusting and explain how each method works. [4]
Question 1 — Multiple-Choice Answer Key
| Question | Answer | Question | Answer | Question | Answer |
|---|---|---|---|---|---|
| 1 | B | 13 | B | 25 | B |
| 2 | C | 14 | A | 26 | B |
| 3 | B | 15 | B | 27 | C |
| 4 | A | 16 | C | 28 | A |
| 5 | A | 17 | A | 29 | A |
| 6 | C | 18 | A | 30 | B |
| 7 | B | 19 | B | 31 | C |
| 8 | B | 20 | C | 32 | D |
| 9 | C | 21 | B | 33 | A |
| 10 | B | 22 | C | 34 | A |
| 11 | D | 23 | D | 35 | B |
| 12 | C | 24 | C | 36 | C |
Question 37 — States of Matter
- 68°C.
- Before heating, particles are closely packed in a regular arrangement and vibrate about fixed positions. During melting, solid and liquid are both present; particles are leaving fixed positions as attractive forces are overcome. In the liquid, particles remain close together but are irregularly arranged and move past one another.
- The supplied energy is used to overcome attractive forces between particles rather than increase their average kinetic energy, so the temperature remains constant.
- Gas particles are far apart, move rapidly and randomly, and have negligible attractive forces. They therefore spread throughout all available space.
- Compression reduces the container volume. The particles strike the walls more frequently, increasing force per unit area and therefore pressure.
- Gas X has a higher relative molecular mass than gas Y. At the same temperature, lighter particles diffuse faster than heavier particles.
Question 38 — Atoms, Elements and Compounds
| Particle | Protons | Neutrons | Electrons |
|---|---|---|---|
| X-27 atom | 13 | 14 | 13 |
| X-29 atom | 13 | 16 | 13 |
| X3+ from X-27 | 13 | 14 | 10 |
- Isotopes are atoms of the same element with the same proton number but different numbers of neutrons.
-
Let the fraction of X-29 be x.
29x + 27(1 − x) = 27.2
2x = 0.2
x = 0.10
Percentage abundance of X-29 = 10% -
X atom: 2,8,3
X3+ ion: 2,8 - X loses three electrons to form X3+. Each Y atom gains one electron to form Y−. Three Y atoms are required, so the formula is XY3. The bonding is ionic.
- There are strong electrostatic attractions between oppositely charged ions in a giant ionic lattice, requiring much energy to overcome. In the solid, the ions are fixed. When molten, the ions are mobile and can carry charge.
Question 39 — Stoichiometry
-
n(Mg) = 3.60 ÷ 24 = 0.150 mol
- 0.150 mol Mg requires 0.300 mol HCl, but only 0.200 mol HCl is present. Therefore, HCl is the limiting reactant.
-
Two moles of HCl produce one mole of hydrogen.
n(H2) = 0.200 ÷ 2 = 0.100 mol
-
Volume = 0.100 × 24 = 2.40 dm³
-
Magnesium reacting = 0.100 mol. Magnesium remaining = 0.150 − 0.100 = 0.050 mol.
Mass remaining = 0.050 × 24 = 1.20 g
-
Percentage yield = (2.16 ÷ 2.40) × 100 = 90.0%
-
n(H2) = 3.60 ÷ 24 = 0.150 mol
n(Mg) = 0.150 mol
Mass of pure Mg = 0.150 × 24 = 3.60 g
Purity = (3.60 ÷ 4.00) × 100 = 90.0%
Question 40 — Electrochemistry
- Electrolysis is the decomposition of an ionic compound, molten or in aqueous solution, using an electric current.
- At the cathode, copper forms as a pink-brown deposit. At the anode, oxygen forms as bubbles. The blue solution becomes paler as Cu2+ ions are removed.
-
Cathode: Cu2+ + 2e− → Cu
Anode: 4OH− → O2 + 2H2O + 4e− - The copper anode loses mass and the cathode gains mass. Copper atoms at the anode form Cu2+ ions, replacing the Cu2+ ions discharged at the cathode.
- The spoon is the cathode. The anode is silver. The electrolyte may be aqueous silver nitrate. Electroplating improves appearance or provides protection from corrosion and wear.
- Advantage: water is the product at point of use, so carbon dioxide and carbon monoxide are not emitted by the vehicle. Disadvantage: hydrogen is difficult to store safely, and its production may require energy from fossil fuels.
Question 41 — Chemical Energetics
- An exothermic reaction transfers thermal energy to the surroundings. Activation energy is the minimum energy that colliding particles must possess for a successful collision.
-
Bonds broken = 4(C–H) + 2(O=O)
= 4(413) + 2(498)
= 1652 + 996
= 2648 kJ/mol -
Bonds formed = 2(C=O) + 4(O–H)
= 2(805) + 4(464)
= 1610 + 1856
= 3466 kJ/mol -
ΔH = energy needed to break bonds − energy released forming bonds
ΔH = 2648 − 3466
ΔH = −818 kJ/mol - More energy is released when product bonds form than is absorbed when reactant bonds break, so the enthalpy change is negative.
- The pathway should show reactants above products, a peak above the reactants, an activation-energy arrow from the reactants to the peak, and a downward ΔH arrow from reactants to products.
- The catalysed pathway has a lower peak. A catalyst provides an alternative pathway with lower activation energy. It does not alter the energy levels of the reactants or products, so ΔH is unchanged.
Question 42 — Chemical Reactions
- Experiment 4. It uses small chips, the higher acid concentration and the higher temperature. These conditions increase collision frequency and the frequency of successful collisions.
- Experiment 2 finishes first because small chips have a larger surface area. Both experiments produce the same final volume because they use the same quantities and concentration of reactants. Particle size changes rate, not final yield.
- At higher temperature, particles move faster and collide more frequently. A greater proportion have energy equal to or greater than the activation energy, so there are more successful collisions per second.
- Increasing temperature shifts equilibrium to the right because the forward reaction is endothermic. Increasing pressure shifts equilibrium to the left because the left side contains fewer moles of gas.
- Carbon monoxide is oxidised because it gains oxygen. Iron(III) oxide is reduced because it loses oxygen. Carbon monoxide is therefore the reducing agent.
Question 43 — Acids, Bases and Salts
-
Copper(II) oxide + sulfuric acid → copper(II) sulfate + water.
CuO + H2SO4 → CuSO4 + H2O
- Copper is below hydrogen in the reactivity series and does not react with dilute sulfuric acid.
- Excess copper(II) oxide ensures that all sulfuric acid is neutralised. Filtration removes excess, unreacted copper(II) oxide. The solution is not heated to dryness because this may remove water of crystallisation or decompose the salt. Cooling allows crystals to form from the concentrated solution.
-
n(H2SO4) = 0.250 × 0.0180 = 0.00450 mol
n(NaOH) = 2 × 0.00450 = 0.00900 mol
Concentration = 0.00900 ÷ 0.0250
= 0.360 mol/dm³ - Mix aqueous barium nitrate with aqueous sodium sulfate. Filter the mixture to collect the precipitate, wash it with distilled water and dry it between filter papers or in a warm oven.
-
H+ + OH− → H2O
Ba2+ + SO42− → BaSO4 - Add aqueous sodium hydroxide and warm gently. Ammonia gas is produced and turns damp red litmus paper blue.
Question 44 — The Periodic Table
- P is sodium, Q is chlorine and R is argon.
-
P: Group I, Period 3.
Q: Group VII, Period 3. - R has a complete outer electron shell and therefore has a stable electronic structure. It has little tendency to gain, lose or share electrons.
- T reacts more vigorously with water. It has more occupied electron shells, so shielding and the distance of the outer electron from the nucleus increase. The nuclear attraction for the outer electron is weaker, so the electron is lost more easily.
-
Reactivity order: chlorine > bromine > iodine. Bromine displaces iodide ions but not chloride ions.
Cl2 + 2I− → 2Cl− + I2
- Transition elements form coloured compounds and can form ions with different charges. Many also act as catalysts.
- The halogens become darker down the group. Their molecules become larger and contain more electrons, so intermolecular forces become stronger. More energy is needed to overcome these forces, increasing melting and boiling points.
Question 45 — Metals
- W > Z > X > Y. W reacts very vigorously with water. Z reacts slowly with water and vigorously with acid. X reacts with acid but not cold water. Y does not react with acid and is therefore below hydrogen.
- W could be potassium because it reacts very vigorously with cold water. X could be zinc because it reacts with acid and its oxide can be reduced by carbon. Y could be copper because it does not react with dilute hydrochloric acid.
- Metals above carbon are too reactive for their oxides to be reduced by carbon and are extracted by electrolysis. Metals below carbon can be extracted by carbon or carbon monoxide because carbon removes oxygen from their oxides.
-
Fe2O3 + 3CO → 2Fe + 3CO2Carbon monoxide is oxidised. Iron(III) oxide is reduced.
- Aircraft: aluminium has a low density and is strong when alloyed. Overhead cables: it has low density and conducts electricity. Food containers: it resists corrosion because of its protective oxide layer and is malleable.
- A pure metal contains regular layers of equal-sized atoms that can slide over one another. Different-sized atoms in an alloy distort the layers and make sliding more difficult.
- Iron requires both oxygen and water to rust. Dissolved salt increases the conductivity of the water, allowing the electrochemical reactions involved in rusting to occur faster.
- Painting, oiling or plastic coating forms a barrier that prevents oxygen and water reaching the iron. Galvanising coats iron with zinc; the zinc acts as a barrier and also provides sacrificial protection because zinc is more reactive than iron.
